-56x-56x^2=0

Solution for -56x-56x^2=0 equation:

-56x-56x^2=0

a = -56; b = -56; c = 0;
Δ = b2-4ac
Δ = -562-4·(-56)·0
Δ = 3136
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3136}=56$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-56)-56}{2*-56}=\frac{0}{-112}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-56)+56}{2*-56}=\frac{112}{-112}
=-1
$